★ COMPARISONS · REPAIR VS REPLACE · X-VS-Y #243

Repair vs Replace Air Conditioner: Cost Calculator 2026

REPAIR wins by $4,100.00 — repair $600.00, replace $4,700.00. A $600 repair beats a $5,500 new air conditioner when the old one has 5 years left — but over 10 years the new air conditioner wins by $1,500.00, because its savings run the full decade. Enter your numbers to find your break-even.

966

Repair vs replace air conditioner — break-even cost calculator

Should you repair or replace your air conditioner? Compare the repair cost against a new air conditioner, with break-even repair cost, new price, remaining life and savings — and see how the answer flips over 10 years.

What the repair will cost, in dollars — parts and labor. The default is $600.

What a new air conditioner costs, in dollars — the price of the model you would buy, before any saving. The default is $5,500.

How many more years the old air conditioner should last after the repair, in years. The default is 5.

How much less the new air conditioner costs to run each year, in dollars per year — energy and fewer service calls. The default is $180 a year.

What it costs to get rid of the old air conditioner, in dollars — haul-away or a tip fee. Set it to $0 if the retailer takes it away free. The default is $100.

REPAIR wins by $4,100.00 — repair $600.00, replace $4,700.00REPAIR wins by $4,100.00 — repair $600.00, replace $4,700.00Repair total $600.00. Replace total $4,700.00. REPAIR wins by $4,100.00. Cost per year: repair $120.00 vs replace $940.00. Break-even repair cost $4,700.00. Break-even new price $1,400.00. Break-even remaining life 27.78 yrs (exact 27.7778). Break-even annual saving $1,000.00/yr. Break-even disposal: none (-$4,000.00). 10-year lens: repair-then-replace $5,300.00 vs replace-now $3,800.00 — REPLACE wins by $1,500.00 over 10 years. The repair wins today because the old air conditioner still has 5 years of life and the new one only saves $180 a year — but over 10 years the new air conditioner’s savings run the full decade, so the verdict flips. The 10-year rule is unclamped: (10 − L) is used as-is, so for L over 10 the repair-then-replace total grows with L. Rounding convention: totals are computed from unrounded values, so rounded parts may differ by a cent from their rounded sum.

Repair total: $600.00

Replace total: $4,700.00

Verdict: REPAIR wins by $4,100.00

Cost per year (repair): $120.00

Cost per year (replace): $940.00

Break-even repair cost: $4,700.00

Break-even new price: $1,400.00

Break-even remaining life: 27.78 yrs (exact 27.7778)

Break-even annual saving: $1,000.00/yr

Break-even disposal: none (-$4,000.00)

10-year: repair-then-replace: $5,300.00

10-year: replace-now: $3,800.00

10-year verdict: REPLACE wins by $1,500.00 over 10 years

Branch: Repair $1,500: Repair $1,500.00, replace $4,700.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years

Branch: Repair $5,000: Repair $5,000.00, replace $4,700.00 — REPLACE wins by $300.00. 10-year: $9,700.00 vs $3,800.00 — REPLACE wins by $5,900.00 over 10 years

Branch: 10 years left: Repair $600.00, replace $3,800.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years

Branch: 12 years left: Repair $600.00, replace $3,440.00 — REPAIR wins by $2,840.00. 10-year: $6,560.00 vs $3,800.00 — REPLACE wins by $2,760.00 over 10 years

Branch: Saving $400/year: Repair $600.00, replace $3,600.00 — REPAIR wins by $3,000.00. 10-year: $4,200.00 vs $1,600.00 — REPLACE wins by $2,600.00 over 10 years

Branch: Saving $0/year: Repair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years

Branch: New air conditioner $3,000: Repair $600.00, replace $2,200.00 — REPAIR wins by $1,600.00. 10-year: $2,800.00 vs $1,300.00 — REPLACE wins by $1,500.00 over 10 years

Branch: New air conditioner $8,000: Repair $600.00, replace $7,200.00 — REPAIR wins by $6,600.00. 10-year: $7,800.00 vs $6,300.00 — REPLACE wins by $1,500.00 over 10 years

Branch: Disposal $0: Repair $600.00, replace $4,600.00 — REPAIR wins by $4,000.00. 10-year: $5,200.00 vs $3,700.00 — REPLACE wins by $1,500.00 over 10 years

Branch: Disposal $500: Repair $600.00, replace $5,100.00 — REPAIR wins by $4,500.00. 10-year: $5,700.00 vs $4,200.00 — REPLACE wins by $1,500.00 over 10 years

Reverse: break-even repair cost: $4,700.00 ($4,700.00)

At that repair cost the repair total is: $4,700.00

At $1 less it is: $4,699.00

At $1 more it is: $4,701.00

At that repair cost the winner is: TIE

At $1 less the winner is: REPAIR wins by $1.00

At $1 more the winner is: REPLACE wins by $1.00

Reverse verdict: TIE

Reverse: break-even new price: $1,400.00 ($1,400.00)

At that new price the replace total is: $600.00

At $1 less it is: $599.00

At $1 more it is: $601.00

At that new price the winner is: TIE

At $1 less the winner is: REPLACE wins by $1.00

At $1 more the winner is: REPAIR wins by $1.00

Reverse verdict: TIE

Reverse: break-even remaining life: 27.7778 (27.78 yrs)

At that life the replace total is: $599.60

At 0.01 yrs less it is: $601.40

At 0.01 yrs more it is: $597.80

At that life the winner is: REPLACE wins by $0.40

At 0.01 yrs less the winner is: REPAIR wins by $1.40

At 0.01 yrs more the winner is: REPLACE wins by $2.20

Reverse verdict: NEAREST

Reverse: break-even annual saving: $1,000.00 ($1,000.00)

At that saving the replace total is: $600.00

At $1/yr less it is: $605.00

At $1/yr more it is: $595.00

At that saving the winner is: TIE

At $1/yr less the winner is: REPAIR wins by $5.00

At $1/yr more the winner is: REPLACE wins by $5.00

Reverse verdict: TIE

Reverse: break-even disposal: none (-$4,000.00) (none (-$4,000.00))

Reverse verdict: NONE

Reverse: 10-year lens: $5,300.00 ($5,300.00)

Replace-now over 10 years: $3,800.00

Replace wins over 10 years by: $1,500.00

Reverse verdict: REPLACE

Edge: repair $0: Repair $0.00, replace $4,700.00 — REPAIR wins by $4,700.00. 10-year: $4,700.00 vs $3,800.00 — REPLACE wins by $900.00 over 10 years

Edge: 1 year left, no saving: Repair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years

Repair it — REPAIR wins by $4,100.00. A $600.00 repair costs far less than the $4,700.00 it costs to replace the air conditioner, because the old unit still has 5 years of life and the new one only saves $180.00 a year. But look at the 10-year lens: over a decade replace wins by $1,500.00 over 10 years, because its savings run the full ten years — if you plan to stay put, replacing now is the cheaper decade.

Repair $1,500: Repair $1,500.00, replace $4,700.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years.

Repair $5,000: Repair $5,000.00, replace $4,700.00 — REPLACE wins by $300.00. 10-year: $9,700.00 vs $3,800.00 — REPLACE wins by $5,900.00 over 10 years.

10 years left: Repair $600.00, replace $3,800.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years.

12 years left: Repair $600.00, replace $3,440.00 — REPAIR wins by $2,840.00. 10-year: $6,560.00 vs $3,800.00 — REPLACE wins by $2,760.00 over 10 years.

Saving $400/year: Repair $600.00, replace $3,600.00 — REPAIR wins by $3,000.00. 10-year: $4,200.00 vs $1,600.00 — REPLACE wins by $2,600.00 over 10 years.

Saving $0/year: Repair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years.

New air conditioner $3,000: Repair $600.00, replace $2,200.00 — REPAIR wins by $1,600.00. 10-year: $2,800.00 vs $1,300.00 — REPLACE wins by $1,500.00 over 10 years.

New air conditioner $8,000: Repair $600.00, replace $7,200.00 — REPAIR wins by $6,600.00. 10-year: $7,800.00 vs $6,300.00 — REPLACE wins by $1,500.00 over 10 years.

Disposal $0: Repair $600.00, replace $4,600.00 — REPAIR wins by $4,000.00. 10-year: $5,200.00 vs $3,700.00 — REPLACE wins by $1,500.00 over 10 years.

Disposal $500: Repair $600.00, replace $5,100.00 — REPAIR wins by $4,500.00. 10-year: $5,700.00 vs $4,200.00 — REPLACE wins by $1,500.00 over 10 years.

Reverse: the break-even repair cost is $4,700.00 (exact $4,700.00); a $4,700.00 repair costs $4,700.00, exactly tying the replace total — verdict: TIE. The break-even new price is $1,400.00 (exact $1,400.00); a $1,400.00 air conditioner costs $600.00 to replace, tying the repair — verdict: TIE. The break-even remaining life is 27.78 yrs (exact 27.7778); at 27.78 yrs the replace total is $599.60 (REPLACE wins by $0.40), at 27.77 yrs it is $601.40 (REPAIR wins by $1.40) — 27.7778 is the exact tie. The break-even annual saving is $1,000.00/yr (exact $1,000.00); at $1,000.00/yr saving the replace total is $600.00, tying the repair — verdict: TIE. The break-even disposal is none — the disposal cost that would tie is -$4,000.00; repairing wins even with free disposal — verdict: NONE. The 10-year lens: repair-then-replace $5,300.00 vs replace-now $3,800.00 — REPLACE wins by $1,500.00 over 10 years.

The repair wins today — the replacement wins the decade

An air conditioner repair is cheap and a new air conditioner is not — but a new unit runs cheaper every year, and over a decade that saving adds up. The repair total is just the repair cost: $600.00. The replace total is the new price, minus the saving over the old unit’s remaining life, plus disposal: $5,500 − $180 × 5 + $100 = $4,700.00. On the defaults — repair $600.00, new air conditioner $5,500.00, remaining life 5 years, saving $180.00/year, disposal $100.00 — REPAIR wins by $4,100.00; cost per year repair $120.00 vs replace $940.00; break-even repair $4,700.00, break-even price $1,400.00, break-even life 27.78 yrs (exact 27.7778), break-even saving $1,000.00/yr, break-even disposal none (-$4,000.00); 10-year repair-then-replace $5,300.00 vs replace-now $3,800.00 — REPLACE wins by $1,500.00 over 10 years.

ScenarioRepairReplaceWinnerBy10-year winner
Default$600.00$4,700.00REPAIR wins by $4,100.00$4,100.00REPLACE wins by $1,500.00 over 10 years
Repair $1,500$1,500.00$4,700.00REPAIR wins by $3,200.00$3,200.00REPLACE wins by $2,400.00 over 10 years
Repair $5,000$5,000.00$4,700.00REPLACE wins by $300.00$300.00REPLACE wins by $5,900.00 over 10 years
10 years left$600.00$3,800.00REPAIR wins by $3,200.00$3,200.00REPLACE wins by $2,400.00 over 10 years
12 years left$600.00$3,440.00REPAIR wins by $2,840.00$2,840.00REPLACE wins by $2,760.00 over 10 years
Saving $400/year$600.00$3,600.00REPAIR wins by $3,000.00$3,000.00REPLACE wins by $2,600.00 over 10 years
Saving $0/year$600.00$5,600.00REPAIR wins by $5,000.00$5,000.00REPLACE wins by $600.00 over 10 years
New air conditioner $3,000$600.00$2,200.00REPAIR wins by $1,600.00$1,600.00REPLACE wins by $1,500.00 over 10 years
New air conditioner $8,000$600.00$7,200.00REPAIR wins by $6,600.00$6,600.00REPLACE wins by $1,500.00 over 10 years
Disposal $0$600.00$4,600.00REPAIR wins by $4,000.00$4,000.00REPLACE wins by $1,500.00 over 10 years
Disposal $500$600.00$5,100.00REPAIR wins by $4,500.00$4,500.00REPLACE wins by $1,500.00 over 10 years

At the defaults — repair $600.00, new air conditioner $5,500.00, remaining life 5 years, saving $180.00/year, disposal $100.00 — the repair total is $600.00, the replace total is $4,700.00, REPAIR wins by $4,100.00; cost per year repair $120.00 vs replace $940.00; break-even repair $4,700.00, break-even price $1,400.00, break-even life 27.78 yrs (exact 27.7778), break-even saving $1,000.00/yr, break-even disposal none (-$4,000.00); 10-year repair-then-replace $5,300.00 vs replace-now $3,800.00 — REPLACE wins by $1,500.00 over 10 years. Check the identities: repair = R; replace = P − S × L + D; difference = replace − repair; break-even repair cost = replace total; break-even new price = R + S × L − D; break-even remaining life = (P + D − R) ÷ S; break-even annual saving = (P + D − R) ÷ L; break-even disposal = R − P + S × L; 10-year repair-then-replace = R + P + D − S × (10 − L); 10-year replace-now = P + D − S × 10. Rounding convention: totals are computed from unrounded values, so rounded parts may differ by a cent from their rounded sum.

The worked example, line by line

Setup: repair $600.00, new air conditioner $5,500.00, remaining life 5 years, saving $180.00/year, disposal $100.00.

Line 1 — the repair total. The repair total is the repair cost: $600.00.

Line 2 — the replace total. $5,500 − $180 × 5 + $100 = $5,500 − $900 + $100 = $4,700.00. The five years of saving shave $900 off the new unit’s price.

Line 3 — the winner. $4,700.00 − $600.00 = $4,100.00, so REPAIR wins by $4,100.00. Cost per year: $600 ÷ 5 = $120.00 for the repair, $4,700 ÷ 5 = $940.00 for the replacement.

Line 4 — the break-evens. The break-even repair cost is the replace total, $4,700.00. The break-even new price is $600 + $180 × 5 − $100 = $1,400.00. The break-even remaining life is ($5,500 + $100 − $600) ÷ $180 = 27.78 yrs (exact 27.7778). The break-even annual saving is ($5,500 + $100 − $600) ÷ 5 = $1,000.00/yr. The break-even disposal is $600 − $5,500 + $180 × 5 = -$4,000.00 — none, because the disposal cost that would tie is negative.

Line 5 — the 10-year lens. Repair now, then replace in 5 years: $600 + $5,500 + $100 − $180 × 5 = $5,300.00. Replace now: $5,500 + $100 − $180 × 10 = $3,800.00. So REPLACE wins by $1,500.00 over 10 years — the verdict flips over 10 years.

Reverse: the break-even repair cost is $4,700.00 (exact $4,700.00); a $4,700.00 repair costs $4,700.00, exactly tying the replace total — verdict: TIE. The break-even new price is $1,400.00 (exact $1,400.00); a $1,400.00 air conditioner costs $600.00 to replace, tying the repair — verdict: TIE. The break-even remaining life is 27.78 yrs (exact 27.7778); at 27.78 yrs the replace total is $599.60 (REPLACE wins by $0.40), at 27.77 yrs it is $601.40 (REPAIR wins by $1.40), at 27.79 yrs it is $597.80 (REPLACE wins by $2.20) — 27.7778 is the exact tie. The break-even annual saving is $1,000.00/yr (exact $1,000.00); at $1,000.00/yr saving the replace total is $600.00, tying the repair — verdict: TIE. The break-even disposal is none — the disposal cost that would tie is -$4,000.00; repairing wins even with free disposal — verdict: NONE. The 10-year lens: repair-then-replace $5,300.00 vs replace-now $3,800.00 — REPLACE wins by $1,500.00 over 10 years.

Every branch, checked

Repair $1,500: Repair $1,500.00, replace $4,700.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years. A $1,500 repair is still far cheaper than replacing — REPAIR wins by $3,200.00.

Repair $5,000: Repair $5,000.00, replace $4,700.00 — REPLACE wins by $300.00. 10-year: $9,700.00 vs $3,800.00 — REPLACE wins by $5,900.00 over 10 years. At $5,000 the repair costs more than the $4,700.00 replacement — REPLACE wins by $300.00, a flip from the default verdict.

10 years left: Repair $600.00, replace $3,800.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years. Ten years of $180 savings are worth $1,800, so the replace total falls to $3,800.00 — but REPAIR wins by $3,200.00 today; the 10-year lens is still REPLACE by $2,400.00.

12 years left: Repair $600.00, replace $3,440.00 — REPAIR wins by $2,840.00. 10-year: $6,560.00 vs $3,800.00 — REPLACE wins by $2,760.00 over 10 years. Twelve years of saving drop the replace total to $3,440.00 — REPAIR wins by $2,840.00 today. And the 10-year repair-then-replace is $6,560.00 — the unclamped (10 − L) = −2 means the replacement you buy in 12 years is charged with negative saving, so the path costs more, not less.

Saving $400/year: Repair $600.00, replace $3,600.00 — REPAIR wins by $3,000.00. 10-year: $4,200.00 vs $1,600.00 — REPLACE wins by $2,600.00 over 10 years. A $400-a-year saving pays for the new unit fast — the replace total is $3,600.00 and REPAIR wins by $3,000.00; over 10 years the replace-now total is $1,600.00.

Saving $0/year: Repair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years. With no saving the new unit costs its full price plus disposal — $5,600.00 — so REPAIR wins by $5,000.00 and the break-even remaining life is — (no saving, so no life ever ties).

New air conditioner $3,000: Repair $600.00, replace $2,200.00 — REPAIR wins by $1,600.00. 10-year: $2,800.00 vs $1,300.00 — REPLACE wins by $1,500.00 over 10 years. A cheaper new unit narrows the gap to $2,200.00 — but REPAIR wins by $1,600.00, the closest call on the page.

New air conditioner $8,000: Repair $600.00, replace $7,200.00 — REPAIR wins by $6,600.00. 10-year: $7,800.00 vs $6,300.00 — REPLACE wins by $1,500.00 over 10 years. An $8,000 unit is thirteen times the repair — REPAIR wins by $6,600.00.

Disposal $0: Repair $600.00, replace $4,600.00 — REPAIR wins by $4,000.00. 10-year: $5,200.00 vs $3,700.00 — REPLACE wins by $1,500.00 over 10 years. Free haul-away drops the replace total to $4,600.00 — REPAIR wins by $4,000.00.

Disposal $500: Repair $600.00, replace $5,100.00 — REPAIR wins by $4,500.00. 10-year: $5,700.00 vs $4,200.00 — REPLACE wins by $1,500.00 over 10 years. A $500 disposal fee pushes the replace total to $5,100.00 — REPAIR wins by $4,500.00.

What the defaults assume

The model assumes the repair restores the old air conditioner for its full remaining life, and that the new unit’s saving is the same every year — it does not model a repair that fails again, a new unit that breaks early, or energy prices changing. It assumes the disposal fee is paid when you replace, not when you repair — you keep the old unit either way. It assumes the saving is real money: $180 a year of lower energy and fewer service calls. With a $0 repair the total is $0.00 and REPAIR wins by $4,700.00, but the 10-year lens is still REPLACE by $900.00. With 1 year left and no saving the break-even life is — — at the model level there is no life that ties, because the saving is $0; at the calc level S = 0 is valid input and the break-even-life field renders —. Rounding convention: totals are computed from unrounded values, so rounded parts may differ by a cent from their rounded sum; the reverses are nearest-value solutions, and the exact unrounded figures ($4,700.00, $1,400.00, 27.7778, $1,000.00, -$4,000.00) are stated wherever the rounded figures appear.

Output · formula · meaning

OutputFormulaWhat it means
Repair totalthe repair cost R$600.00.
Replace totalnew price − saving × life + disposal$4,700.00.
Differencereplace total − repair total$4,100.00.
WinnerREPAIR when the difference is positive, REPLACE when negativeREPAIR wins by $4,100.00.
Cost per year (repair)repair cost ÷ remaining life$120.00.
Cost per year (replace)replace total ÷ remaining life$940.00.
Break-even repair costthe replace total$4,700.00.
Break-even new pricerepair + saving × life − disposal$1,400.00.
Break-even remaining life(new price + disposal − repair) ÷ saving27.7778 yrs → 27.78 yrs.
Break-even annual saving(new price + disposal − repair) ÷ life$1,000.00/yr.
Break-even disposalrepair − new price + saving × life-$4,000.00 → none.
10-year: repair-then-replacerepair + new price + disposal − saving × (10 − life)$5,300.00.
10-year: replace-nownew price + disposal − saving × 10$3,800.00.
10-year winnerthe smaller 10-year totalREPLACE wins by $1,500.00 over 10 years.
Break-even repair costthe replace total$4,700.00 → $4,700.00.
Break-even new pricerepair + saving × life − disposal$1,400.00 → $1,400.00.
Break-even remaining life(new price + disposal − repair) ÷ saving27.7778 → 27.78 yrs.
Break-even annual saving(new price + disposal − repair) ÷ life$1,000.00/yr → $1,000.00/yr.
Break-even disposalrepair − new price + saving × life-$4,000.00 → none.
10-year lensrepair-then-replace vs replace-now$5,300.00 vs $3,800.00.
Repair $1,500same modelRepair $1,500.00, replace $4,700.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years.
Repair $5,000same modelRepair $5,000.00, replace $4,700.00 — REPLACE wins by $300.00. 10-year: $9,700.00 vs $3,800.00 — REPLACE wins by $5,900.00 over 10 years.
10 years leftsame modelRepair $600.00, replace $3,800.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years.
12 years leftsame modelRepair $600.00, replace $3,440.00 — REPAIR wins by $2,840.00. 10-year: $6,560.00 vs $3,800.00 — REPLACE wins by $2,760.00 over 10 years.
Saving $400/yearsame modelRepair $600.00, replace $3,600.00 — REPAIR wins by $3,000.00. 10-year: $4,200.00 vs $1,600.00 — REPLACE wins by $2,600.00 over 10 years.
Saving $0/yearsame modelRepair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years.
New air conditioner $3,000same modelRepair $600.00, replace $2,200.00 — REPAIR wins by $1,600.00. 10-year: $2,800.00 vs $1,300.00 — REPLACE wins by $1,500.00 over 10 years.
New air conditioner $8,000same modelRepair $600.00, replace $7,200.00 — REPAIR wins by $6,600.00. 10-year: $7,800.00 vs $6,300.00 — REPLACE wins by $1,500.00 over 10 years.
Disposal $0same modelRepair $600.00, replace $4,600.00 — REPAIR wins by $4,000.00. 10-year: $5,200.00 vs $3,700.00 — REPLACE wins by $1,500.00 over 10 years.
Disposal $500same modelRepair $600.00, replace $5,100.00 — REPAIR wins by $4,500.00. 10-year: $5,700.00 vs $4,200.00 — REPLACE wins by $1,500.00 over 10 years.

Who uses this

  • The homeowner with a $600 repair quote: they learn REPAIR wins by $4,100.00 — and they check the $5,000 branch (REPLACE wins by $300.00) to see the repair price where replacing wins.
  • The owner whose unit has 12 years left: they learn REPAIR wins by $2,840.00 — twelve years of saving still lose to the cheap repair today — and they check the 10-year branch (REPLACE wins by $2,400.00 over 10 years) to see the decade margin.
  • The shopper eyeing a $3,000 air conditioner: they learn REPAIR wins by $1,600.00 — the closest call on the page — and they check the $8,000 branch (REPAIR wins by $6,600.00) to see how fast a dearer model loses.
  • The planner thinking in decades: they learn the 10-year lens flips the verdict — REPLACE wins by $1,500.00 over 10 years — and they check the $400-a-year branch (REPLACE wins by $2,600.00 over 10 years) to see the decade margin widen.

Accuracy & limitations

The math is first-principles comparison: repair = R; replace = P − S × L + D; difference = replace − repair; cost per year = total ÷ L; break-even repair cost = replace total; break-even new price = R + S × L − D; break-even remaining life = (P + D − R) ÷ S; break-even annual saving = (P + D − R) ÷ L; break-even disposal = R − P + S × L; 10-year repair-then-replace = R + P + D − S × (10 − L); 10-year replace-now = P + D − S × 10. The 4-decimal exact is shown where the rounding matters: the break-even remaining life is 27.7778 (shown as 27.78 yrs); at 27.78 yrs the replace total is $599.60 (REPLACE wins by $0.40), at 27.77 yrs it is $601.40 (REPAIR wins by $1.40), at 27.79 yrs it is $597.80 (REPLACE wins by $2.20). What the model cannot do is predict an air conditioner’s real life: a repair can fail again, a new unit can break early, and the saving depends on how much you run it — the break-even life of 27.78 yrs is the number to compare against your honest estimate of the old unit’s remaining life. For the same question on a smaller appliance, see the repair vs replace washing machine calculator and the repair vs replace refrigerator calculator; for the size of the unit itself, see the air conditioner size chart. This is a calculator, not a repair manual.

Cite this calculatorBright Side Kit. “Repair vs Replace Air Conditioner: Cost Calculator 2026” brightoolbox.com, 2026. Method: repair total = R; replace total = P − S × L + D; difference = replace − repair (> 0 means REPAIR wins, < 0 means REPLACE wins, 0 = tie); cost per year (repair) = R / L; cost per year (replace) = replace total / L; break-even repair cost = replace total; break-even new price = R + S × L − D; break-even remaining life = (P + D − R) / S; break-even annual saving = (P + D − R) / L; break-even disposal = R − P + S × L; 10-year lens: repair now then replace at the end of the remaining life = R + P + D − S × (10 − L); replace now = P + D − S × 10. The 10-year rule is unclamped: (10 − L) is used as-is, so for L over 10 the repair-then-replace total grows with L. Key idea: the repair wins today because the old unit still has life and the new one saves little — but over 10 years the new unit’s savings run the full decade, so the verdict flips. Defaults: repair $600, new air conditioner $5,500, remaining life 5 years, saving $180/year, disposal $100 → repair $600.00, replace $4,700.00, REPAIR wins by $4,100.00; cost per year repair $120.00 vs replace $940.00; break-even repair $4,700.00, break-even price $1,400.00, break-even life 27.78 yrs (exact 27.7778), break-even saving $1,000.00/yr, break-even disposal none (-$4,000.00); 10-year repair-then-replace $5,300.00 vs replace-now $3,800.00, REPLACE wins by $1,500.00 over 10 years. Branches: Repair $1,500 → Repair $1,500.00, replace $4,700.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years; Repair $5,000 → Repair $5,000.00, replace $4,700.00 — REPLACE wins by $300.00. 10-year: $9,700.00 vs $3,800.00 — REPLACE wins by $5,900.00 over 10 years; 10 years left → Repair $600.00, replace $3,800.00 — REPAIR wins by $3,200.00. 10-year: $6,200.00 vs $3,800.00 — REPLACE wins by $2,400.00 over 10 years; 12 years left → Repair $600.00, replace $3,440.00 — REPAIR wins by $2,840.00. 10-year: $6,560.00 vs $3,800.00 — REPLACE wins by $2,760.00 over 10 years (10-year repair-then-replace $6,560.00 uses the unclamped (10 − L) = −2); Saving $400/year → Repair $600.00, replace $3,600.00 — REPAIR wins by $3,000.00. 10-year: $4,200.00 vs $1,600.00 — REPLACE wins by $2,600.00 over 10 years; Saving $0/year → Repair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years; New air conditioner $3,000 → Repair $600.00, replace $2,200.00 — REPAIR wins by $1,600.00. 10-year: $2,800.00 vs $1,300.00 — REPLACE wins by $1,500.00 over 10 years; New air conditioner $8,000 → Repair $600.00, replace $7,200.00 — REPAIR wins by $6,600.00. 10-year: $7,800.00 vs $6,300.00 — REPLACE wins by $1,500.00 over 10 years; Disposal $0 → Repair $600.00, replace $4,600.00 — REPAIR wins by $4,000.00. 10-year: $5,200.00 vs $3,700.00 — REPLACE wins by $1,500.00 over 10 years; Disposal $500 → Repair $600.00, replace $5,100.00 — REPAIR wins by $4,500.00. 10-year: $5,700.00 vs $4,200.00 — REPLACE wins by $1,500.00 over 10 years. Reverses: break-even repair cost = $4,700.00 (exact $4,700.00; a $4,700.00 repair costs $4,700.00, exactly tying the replace total); break-even new price = $1,400.00 (exact $1,400.00; a $1,400.00 air conditioner costs $600.00 to replace, tying the repair); break-even remaining life = 27.78 yrs (exact 27.7778; at 27.78 yrs the replace total is $599.60, REPLACE wins by $0.40; at 27.77 yrs it is $601.40, REPAIR wins by $1.40); break-even annual saving = $1,000.00/yr (exact $1,000.00; at $1,000.00/yr saving the replace total is $600.00, tying the repair); break-even disposal = none (the disposal cost that would tie is -$4,000.00; repairing wins even with free disposal); 10-year lens: repair-then-replace $5,300.00 vs replace-now $3,800.00, REPLACE wins by $1,500.00 over 10 years. Edges: repair $0 → Repair $0.00, replace $4,700.00 — REPAIR wins by $4,700.00. 10-year: $4,700.00 vs $3,800.00 — REPLACE wins by $900.00 over 10 years; 1 year left, no saving → Repair $600.00, replace $5,600.00 — REPAIR wins by $5,000.00. 10-year: $6,200.00 vs $5,600.00 — REPLACE wins by $600.00 over 10 years (break-even life —). Bright Side Kit. "Repair vs Replace Air Conditioner: Cost Calculator 2026" https://brightoolbox.com/repair-vs-replace-air-conditioner/ Accessed October 25, 2026.
Embed this calculator

Paste this into any web page to embed the live calculator. The “Powered by Bright Side Kit” link below it must stay intact.

Frequently asked questions

Should I repair or replace my air conditioner?

Repair it — REPAIR wins by $4,100.00. A $600 repair beats a $5,500 new air conditioner when the old one has 5 years left: repair $600.00, replace $4,700.00. But over 10 years the new unit wins by $1,500.00 — so repair now if you might move, replace now if you will stay.

What repair cost makes replacing the better choice?

$4,700.00. The break-even repair cost is $4,700.00 — a $4,700.00 repair exactly ties the replace total. At $5,000 the replacement already wins by $300.00.

How long must my old air conditioner last for the repair to pay off?

27.78 years. The break-even remaining life is 27.78 yrs (exact 27.7778). If the old unit will last more than 27.78 years after the repair, replacing wins — which almost never happens, so the repair usually wins today.

How much must a new air conditioner save each year to win?

$1,000.00/yr. The break-even annual saving is $1,000.00/yr — at $1,000.00/yr saving the replace total is $600.00, tying the repair. At $400/yr the repair still wins by $3,000.00.

Does the disposal fee change the answer?

Rarely — it would have to be negative here. The disposal cost that would tie is -$4,000.00, so repairing wins even with free disposal. At a $500 disposal fee the repair wins by $4,500.00.

Why does the 10-year lens flip the verdict?

Because the new unit’s saving runs the full decade. Over 10 years the repair-then-replace path costs $5,300.00 and replacing now costs $3,800.00 — REPLACE wins by $1,500.00 over 10 years. The repair only wins today because the old unit still has 5 years left.

What if the repair is free?

Repair it — REPAIR wins by $4,700.00. A $0 repair beats the $4,700.00 replacement by the full $4,700.00. But the 10-year lens still favors replacing, by $900.00 — a free repair now and a new unit later still costs more over the decade.

What if the new air conditioner saves nothing?

Repair it — REPAIR wins by $5,000.00. With no saving the new unit costs its full price plus disposal — $5,600.00 — so the repair wins by $5,000.00 and there is no break-even remaining life.